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NEET CHEMISTRYP Block ElementsMedium

Question

Which of the following statements is incorrect?

A

NaHCO3NaHCO_3 on heating gives Na2CO3Na_2CO_3.

B

Pure sodium metal dissolves in liquid ammonia to give a blue solution.

C

NaOH reacts with glass to give sodium silicate.

D

Aluminium reacts with excess NaOH to give Al(OH)3Al(OH)_3.

Step-by-Step Solution

  1. Option A is correct: Sodium hydrogen carbonate (NaHCO3NaHCO_3) thermally decomposes to give sodium carbonate (Na2CO3Na_2CO_3), water, and carbon dioxide.
  2. Option B is correct: Alkali metals like sodium dissolve in liquid ammonia to give deep blue solutions which are conducting in nature due to ammoniated electrons.
  3. Option C is correct: Sodium hydroxide (NaOHNaOH) reacts with silica (SiO2SiO_2), a major component of glass, to form sodium silicate (Na2SiO3Na_2SiO_3). This causes etching of glass.
  4. Option D is incorrect: Aluminium is an amphoteric metal. It reacts with excess aqueous sodium hydroxide to form a soluble complex, sodium tetrahydroxidoaluminate(III) (or sodium aluminate), and liberates hydrogen gas. The reaction is: 2Al(s)+2NaOH(aq)+6H2O(l)→2Na+[Al(OH)4]−(aq)+3H2(g)2Al(s) + 2NaOH(aq) + 6H_2O(l) \rightarrow 2Na^+[Al(OH)_4]^-(aq) + 3H_2(g) It does not form insoluble aluminium hydroxide (Al(OH)3Al(OH)_3) in excess alkali.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementsfollowingstatementsincorrect

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