A student measured the diameter of a small steel ball using a screw gauge of least count $0.001$ cm. The main

Question

A student measured the diameter of a small steel ball using a screw gauge of least count $0.001$ cm. The main scale reading is $5$ mm and zero of circular scale division coincides with $25$ divisions above the reference level. If screw gauge has a zero error of $-0.004$ cm, the correct diameter of the ball is

Accepted Answer

Diameter of the ball = MSR + CSR $	imes$ (Least count) $-$ Zero error = $0.5$ cm + $25 	imes 0.001 - (-0.004)$ = $0.5 + 0.025 + 0.004$ = $0.529$ cm

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