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NEET generalGeneralMedium

Question

In the reaction: (Phenol + CHCl3CHCl_3 + NaOHNaOH -> Salicylaldehyde derivative), the electrophile involved is

A

Dichloromethyl anion (CHCl2)(\overset{\ominus}{C}HCl_2)

B

Formyl cation (CHO)(\overset{\oplus}{C}HO)

C

Dichloromethyl cation (CHCl2)(\overset{\oplus}{C}HCl_2)

D

Dichlorocarbene (:CCl2)(:CCl_2)

Step-by-Step Solution

This is the Reimer-Tiemann reaction. The electrophile formed is :CCl2:CCl_2 (Dichlorocarbene) according to the reaction: CHCl3+OHCCl3+H2OCHCl_3 + OH^- \rightleftharpoons \overset{\ominus}{C}Cl_3 + H_2O, followed by CCl3:CCl2+Cl\overset{\ominus}{C}Cl_3 \rightarrow :CCl_2 + Cl^-.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

generalreactionphenolsalicylaldehydederivativeelectrophile

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