A ball is projected with velocity $v_0$ at an angle of elevation $30^{\circ}$. Mark the correct statement.

Question

Accepted Answer

1.  **Horizontal Motion:** In projectile motion (neglecting air resistance), there is no force acting on the particle in the horizontal direction ($F_x = 0$). According to Newton's Second Law, if the net force is zero, momentum is conserved. Since acceleration $a_x = 0$, the horizontal velocity $v_x$ remains constant, and thus the horizontal component of momentum ($p_x = mv_x$) is conserved .
2.  **Vertical Motion:** A constant force of gravity acts downwards, causing the vertical velocity component to change continuously. Thus, the vertical component of momentum is not conserved.
3.  **Energy Analysis:**
    *   At the highest point, the vertical velocity is zero, but the horizontal velocity is non-zero ($v_x = v_0 \cos 30^{\circ}$). Therefore, kinetic energy is not zero .
    *   At the highest point, the height is maximum, so the gravitational potential energy ($mgh$) is maximum, not minimum.

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