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NEET PHYSICSWORK, ENERGY AND POWERMedium

Question

A body of mass 1 kg1\text{ kg} begins to move under the action of a time-dependent force F=(2ti^+3t2j^) N\vec{F}=(2t\hat i+3t^2\hat j)\text{ N}, where i^\hat i and j^\hat j are unit vectors along the xx and yy-axis. What power will be developed by the force at the time tt?

A

(2t2+4t4) W(2t^2+4t^4)\text{ W}

B

(2t3+3t3) W(2t^3+3t^3)\text{ W}

C

(2t3+3t5) W(2t^3+3t^5)\text{ W}

D

(2t3+3t4) W(2t^3+3t^4)\text{ W}

Step-by-Step Solution

  1. Identify Acceleration: According to Newton's Second Law, F=ma\vec{F} = m\vec{a}. Given m=1 kgm = 1\text{ kg}, the acceleration is a=F/1=2ti^+3t2j^\vec{a} = \vec{F}/1 = 2t\hat i + 3t^2\hat j [Class 11 Physics, Ch 4, Sec 4.5, Eq 4.5].
  2. Calculate Velocity: Velocity is the time integral of acceleration. Assuming the body starts from rest (v=0v=0 at t=0t=0): v=adt=(2ti^+3t2j^)dt\vec{v} = \int \vec{a} dt = \int (2t\hat i + 3t^2\hat j) dt v=t2i^+t3j^\vec{v} = t^2\hat i + t^3\hat j
  3. Calculate Power: Instantaneous power (PP) is the dot product of force and velocity. P=FvP = \vec{F} \cdot \vec{v} [Class 11 Physics, Ch 5, Sec 5.10, Eq 5.21] P=(2ti^+3t2j^)(t2i^+t3j^)P = (2t\hat i + 3t^2\hat j) \cdot (t^2\hat i + t^3\hat j) P=(2t)(t2)+(3t2)(t3)=2t3+3t5 WP = (2t)(t^2) + (3t^2)(t^3) = 2t^3 + 3t^5\text{ W}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from WORK, ENERGY AND POWER. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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