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NEET PHYSICSMechanical Properties of FluidEasy

Question

A fluid of density ρ\rho is flowing in a pipe of varying cross-sectional area as shown in the figure. Bernoulli's equation for the motion becomes:

A

p+12ρv2+ρgh=constantp+\frac{1}{2}\rho v^2+\rho gh = \text{constant}

B

p+12ρv2=constantp+\frac{1}{2}\rho v^2 = \text{constant}

C

12ρv2+ρgh=constant\frac{1}{2}\rho v^2+\rho gh = \text{constant}

D

p+ρgh=constantp+\rho gh = \text{constant}

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