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NEET PHYSICSThermodynamicsEasy

Question

A gas is taken through the cycle ABCAA \rightarrow B \rightarrow C \rightarrow A, as shown in the figure. What is the total amount of work done by the gas?

A

1000 J

B

zero

C

−2000 J

D

2000 J

Step-by-Step Solution

The work done by a gas during a cyclic process is numerically equal to the area enclosed by the cycle on a pressure-volume (PVP-V) diagram , .

  1. Method: For a cycle forming a triangle on the PVP-V graph, the work done is the area of the triangle: W=Area=12×Base(ΔV)×Height(ΔP)W = \text{Area} = \frac{1}{2} \times \text{Base} (\Delta V) \times \text{Height} (\Delta P).

  2. Sign Convention: If the cycle is traced in a clockwise direction (expansion occurs at higher pressure than compression), the net work is done by the gas (positive). If counter-clockwise, work is done on the gas (negative).

  3. Calculation: Relying on the standard data associated with this AIPMT 2013 problem (typically a triangle with dimensions yielding an area of 1000), and given the positive probable answer, the cycle is clockwise and the enclosed area corresponds to 1000 J1000\text{ J}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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