A man of mass 80 kg is standing in an elevator which is moving with an acceleration of 6 m/s² in the upward di

Question

A man of mass 80 kg is standing in an elevator which is moving with an acceleration of 6 m/s² in the upward direction. The apparent weight of the man will be (g = 10 m/s²):

Accepted Answer

1. **Identify the Forces:** The forces acting on the man are:
   - **Weight ($mg$):** Acting vertically downwards. $W = 80 	ext{ kg} 	imes 10 	ext{ m/s}^2 = 800 	ext{ N}$.
   - **Normal Reaction ($N$):** The force exerted by the floor acting vertically upwards. This is the **apparent weight**.
2. **Apply Newton's Second Law:** The elevator and the man are accelerating upwards with acceleration $a = 6 	ext{ m/s}^2$. The net force $F_{net}$ is in the direction of acceleration (upwards).
   $$ F_{net} = N - mg = ma $$
3. **Solve for Apparent Weight ($N$):**
   $$ N = m(g + a) $$
   $$ N = 80 	ext{ kg} 	imes (10 	ext{ m/s}^2 + 6 	ext{ m/s}^2) $$
   $$ N = 80 	imes 16 $$
   $$ N = 1280 	ext{ N} $$
   [Source 75]

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