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NEET PHYSICSMOTION IN A PLANEEasy

Question

A missile is fired for a maximum range with an initial velocity of 20 m/s20 \text{ m/s}. If g=10 m/s2g=10 \text{ m/s}^2, then the range of the missile will be:

A

50 m

B

60 m

C

20 m

D

40 m

Step-by-Step Solution

  1. Formula for Horizontal Range: The horizontal range RR of a projectile projected with initial velocity v0v_0 at an angle θ0\theta_0 is given by R=v02sin2θ0gR = \frac{v_0^2 \sin 2\theta_0}{g} .
  2. Condition for Maximum Range: The range is maximum when sin2θ0\sin 2\theta_0 is maximum, i.e., sin2θ0=1\sin 2\theta_0 = 1, which implies 2θ0=902\theta_0 = 90^\circ or θ0=45\theta_0 = 45^\circ.
  3. Maximum Range Formula: The maximum horizontal range is Rmax=v02gR_{max} = \frac{v_0^2}{g} .
  4. Calculation: Given v0=20 m/sv_0 = 20 \text{ m/s} and g=10 m/s2g = 10 \text{ m/s}^2. Rmax=(20)210=40010=40 mR_{max} = \frac{(20)^2}{10} = \frac{400}{10} = 40 \text{ m}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEmissilemaximuminitialvelocitymissile

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