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NEET PHYSICSMOTION IN A PLANEEasy

Question

A particle (A) is dropped from a height and another particle (B) is thrown in the horizontal direction with a speed of 5 m/sec from the same height. The correct statement is:

A

Both particles will reach at ground simultaneously

B

Both particles will reach at ground with same speed

C

Particle (A) will reach at ground first with respect to particle (B)

D

Particle (B) will reach at ground first with respect to particle (A)

Step-by-Step Solution

  1. Independence of Motions: The motion of an object can be resolved into independent horizontal (xx) and vertical (yy) components. The vertical motion is acted upon by gravity, while the horizontal motion (ignoring air resistance) has zero acceleration .
  2. Vertical Motion Analysis: Both particles start from the same height hh. Particle A is dropped, so its initial vertical velocity uyA=0u_{yA} = 0. Particle B is thrown horizontally, so its initial vertical velocity is also uyB=0u_{yB} = 0 (its initial velocity is entirely horizontal) .
  3. Time of Flight: The time tt taken to reach the ground depends only on the vertical parameters: h=uyt+12gt2h = u_y t + \frac{1}{2}gt^2. Since uy=0u_y = 0 for both, h=12gt2h = \frac{1}{2}gt^2 implies t=2hgt = \sqrt{\frac{2h}{g}}.
  4. Conclusion: Since hh and gg are the same for both particles, the time tt is the same. Therefore, they reach the ground simultaneously. (Note: Their final speeds will differ because Particle B has a horizontal velocity component, while Particle A does not).

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEparticledroppedheightanotherparticle

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