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NEET PHYSICSNUCLEIEasy

Question

A radioactive nucleus ZAX{}_{Z}^{A}\mathrm{X} undergoes spontaneous decay in the sequence ZXZ1BZ3CZ2D{}_{Z}\mathrm{X} \rightarrow {}_{Z-1}\mathrm{B} \rightarrow {}_{Z-3}\mathrm{C} \rightarrow {}_{Z-2}\mathrm{D}, where ZZ is the atomic number of element X\mathrm{X}. The possible decay particles in the sequence are:

A

β+,α,β\beta^+, \alpha, \beta^-

B

β,α,β+\beta^-, \alpha, \beta^+

C

α,β,β+\alpha, \beta^-, \beta^+

D

α,β+,β\alpha, \beta^+, \beta^-

Step-by-Step Solution

  1. Analyze Step 1 (XZBZ1X_Z \rightarrow B_{Z-1}): The atomic number decreases by 1 (ZZ1Z \rightarrow Z-1). This change is characteristic of β+\beta^+ decay (positron emission), where a proton converts into a neutron, reducing the nuclear charge by 1 unit .
  2. Analyze Step 2 (BZ1CZ3B_{Z-1} \rightarrow C_{Z-3}): The atomic number decreases by 2 (from Z1Z-1 to Z3Z-3). This change corresponds to α\alpha decay, where an \alpha particle (24He{}_{2}^{4}\mathrm{He}) is emitted, reducing the atomic number by 2 .
  3. Analyze Step 3 (CZ3DZ2C_{Z-3} \rightarrow D_{Z-2}): The atomic number increases by 1 (from Z3Z-3 to Z2Z-2). This change is characteristic of β\beta^- decay (electron emission), where a neutron converts into a proton, increasing the nuclear charge by 1 unit .
  4. Conclusion: The sequence of particles emitted is β+,α,β\beta^+, \alpha, \beta^-.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEIradioactivenucleuszamathrmxundergoesspontaneous

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