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NEET PHYSICSUNITS AND MEASUREMENTSEasy

Question

A Screw Gauge gives the following readings when used to measure the diameter of a wire. Main scale reading = 0.0 mm0.0\text{ mm} Circular scale reading = 52 divisions52\text{ divisions} Given that: 1 mm1\text{ mm} on the main scale corresponds to 100 divisions100\text{ divisions} of the circular scale. The diameter of the wire from the above data is:

A

0.026 cm0.026\text{ cm}

B

0.005 cm0.005\text{ cm}

C

0.52 cm0.52\text{ cm}

D

0.052 cm0.052\text{ cm}

Step-by-Step Solution

  1. Determine the Least Count (LC): The pitch of the screw gauge is given as 1 mm1\text{ mm}, and the total number of divisions on the circular scale is 100100. The least count is calculated as LC=PitchTotal circular divisions=1 mm100=0.01 mm\text{LC} = \frac{\text{Pitch}}{\text{Total circular divisions}} = \frac{1\text{ mm}}{100} = 0.01\text{ mm}.
  2. Calculate the Total Reading: The formula for the measurement is Total Reading=Main Scale Reading (MSR)+(Circular Scale Reading (CSR)×LC)\text{Total Reading} = \text{Main Scale Reading (MSR)} + (\text{Circular Scale Reading (CSR)} \times \text{LC}).
  3. Substitute the Values: Total Reading=0.0 mm+(52×0.01 mm)=0.52 mm\text{Total Reading} = 0.0\text{ mm} + (52 \times 0.01\text{ mm}) = 0.52\text{ mm}.
  4. Convert Units: The options are given in centimeters. To convert millimeters to centimeters, divide by 1010. Therefore, the diameter of the wire is 0.52 mm=0.052 cm0.52\text{ mm} = 0.052\text{ cm}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from UNITS AND MEASUREMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSUNITS AND MEASUREMENTSfollowingreadingsmeasurediameterreading

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