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NEET PHYSICSMOTION IN A PLANEEasy

Question

A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 s, what is the magnitude and direction of acceleration of the stone?

A

π24 m/s2\frac{\pi^2}{4} \text{ m/s}^2 and direction along the radius towards the center

B

π2 m/s2\pi^2 \text{ m/s}^2 and direction along the radius away from the center

C

π2 m/s2\pi^2 \text{ m/s}^2 and direction along the radius towards the center

D

π2 m/s2\pi^2 \text{ m/s}^2 and direction along the tangent to the circle

Step-by-Step Solution

  1. Identify Given Values: The problem input contains repeated digits due to formatting errors. Based on the options and standard physics problems (PMT 2005), the values are interpreted as: Radius (rr) = 1 m, Number of revolutions (nn) = 22, Time (tt) = 44 s.
  2. Calculate Angular Velocity (ω\omega): The angular velocity is given by ω=2πnt\omega = \frac{2\pi n}{t}. Substituting values: ω=2π(22)44=44π44=π rad/s\omega = \frac{2\pi (22)}{44} = \frac{44\pi}{44} = \pi \text{ rad/s} .
  3. Calculate Acceleration Magnitude: The acceleration in uniform circular motion is the centripetal acceleration, given by ac=ω2ra_c = \omega^2 r. ac=(π)2(1)=π2 m/s2a_c = (\pi)^2 (1) = \pi^2 \text{ m/s}^2.
  4. Determine Direction: By definition, centripetal acceleration is always directed along the radius towards the center of the circle .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEstringwhirledhorizontalcircleconstant

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