A storage battery of emf 8.0 V and internal resistance 0.5 Ω is being charged by a 120 V DC supply using a ser

Question

A storage battery of emf 8.0 V and internal resistance 0.5 Ω is being charged by a 120 V DC supply using a series resistor of 15.5 Ω. What is the terminal voltage of the battery during charging?

Accepted Answer

According to the NCERT text (Exercise 3.8), when a battery is being charged, the current flows into the positive terminal. First, calculate the current in the circuit: I = (V_supply - ε) / (R + r) = (120 - 8) / (15.5 + 0.5) = 112 / 16 = 7 A. The terminal voltage (V) across a battery during charging is given by V = ε + Ir. Substituting the values: V = 8.0 + (7 × 0.5) = 8.0 + 3.5 = 11.5 V.

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