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NEET PHYSICSThermodynamicsMedium

Question

A thermodynamic system undergoes a cyclic process ABCDAABCDA as shown in Fig. The work done by the system in the cycle is:

A

P0V0P_0 V_0

B

2P0V02 P_0 V_0

C

P0V02\frac{P_0 V_0}{2}

D

zero

Step-by-Step Solution

The work done by a thermodynamic system during a cyclic process is equal to the net area enclosed by the cycle on a P-V diagram.

  1. Sign Convention: The work done is positive if the cycle is traced in a clockwise direction (expansion dominates) and negative if traced in a counter-clockwise direction (compression dominates).
  2. Net Work: If the cycle consists of multiple loops (e.g., a figure-8 shape), the total work is the algebraic sum of the areas of individual loops.

In this specific problem (referencing a standard AIPMT 2014 figure implied by the answer), the cycle ABCDAABCDA typically involves two loops of equal area: one traced clockwise (positive work) and the other counter-clockwise (negative work). If the areas are equal, the positive and negative work cancel each other out, resulting in zero net work done by the system.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermodynamicsthermodynamicsystemundergoescyclicprocess

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