back to directory
NEET PHYSICSThermodynamicsMedium

Question

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is:

A

P0V0P_0V_0

B

2P0V02P_0V_0

C

P0V02\frac{P_0V_0}{2}

D

zero

Step-by-Step Solution

In a PP-VV indicator diagram, the net work done by a thermodynamic system during a cyclic process is equal to the area enclosed by the cycle. If the cyclic process consists of two loops of equal area but traced in opposite directions (one clockwise and one anti-clockwise), the positive work done during the clockwise loop is exactly cancelled out by the negative work done during the anti-clockwise loop. Consequently, the net work done by the system in the complete cycle is zero.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermodynamicsthermodynamicsystemundergoescyclicprocess

More Thermodynamics Questions

View all

The volume ($V$) of a monatomic gas varies with its temperature ($T$), as shown in the graph. The ratio of work done by the gas to the heat absorbed by it when it undergoes a change from state $A$ to state $B$ will be:

A.$\frac{2}{5}$
B.$\frac{2}{3}$
C.$\frac{1}{3}$
D.$\frac{2}{7}$
MediumSolve

A carnot engine having an efficiency of $\frac{1}{10}$ as a heat engine, is used as a refrigerator. If the work done on the system is $10\text{ J}$, the amount of energy absorbed from the reservoir at lower temperature is:

A.$1\text{ J}$
B.$90\text{ J}$
C.$99\text{ J}$
D.$100\text{ J}$
MediumSolve

An engine has an efficiency of $\frac{1}{6}$. When the temperature of the sink is reduced by $62^{\circ}\text{C}$, its efficiency is doubled. The temperature of the source is:

A.$124^{\circ}\text{C}$
B.$37^{\circ}\text{C}$
C.$62^{\circ}\text{C}$
D.$99^{\circ}\text{C}$
MediumSolve

A refrigerator works between $4^{\circ}\text{C}$ and $30^{\circ}\text{C}$. It is required to remove $600 \text{ calories}$ of heat every second to keep the temperature of the refrigerated space constant. The power required will be: (Take, $1 \text{ cal} = 4.2 \text{ Joules}$)

A.23.65 W
B.236.5 W
C.2365 W
D.2.365 W
MediumSolve

When $1 \text{ kg}$ of ice at $0^{\circ}\text{C}$ melts into water at $0^{\circ}\text{C}$, the resulting change in its entropy, taking the latent heat of ice to be $80 \text{ cal/g}$, is:

A.$8 \times 10^4 \text{ cal/K}$
B.$80 \text{ cal/K}$
C.$293 \text{ cal/K}$
D.$273 \text{ cal/K}$
EasySolve

One mole of an ideal diatomic gas undergoes a transition from $A$ to $B$ along a path $AB$ as shown in the figure. The change in internal energy of the gas during the transition is

A.$20\text{ kJ}$
B.$-20\text{ kJ}$
C.$20\text{ J}$
D.$-12\text{ kJ}$
MediumSolve

The coefficient of performance of a refrigerator is $5$. If the temperature inside freezer is $-20^\circ\text{C}$, the temperature of the surroundings to which it rejects heat is

A.$31^\circ\text{C}$
B.$41^\circ\text{C}$
C.$11^\circ\text{C}$
D.$21^\circ\text{C}$
MediumSolve

A mass of diatomic gas ($\gamma=1.4$) at a pressure of $2\text{ atm}$ is compressed adiabatically so that its temperature rises from $27^\circ\text{C}$ to $927^\circ\text{C}$. The pressure of the gas in the final state is:

A.$28\text{ atm}$
B.$68.7\text{ atm}$
C.$256\text{ atm}$
D.$8\text{ atm}$
MediumSolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →