After passing through a polarizer, a linearly polarized light of intensity $I$ is incident on an analyser maki

Question

After passing through a polarizer, a linearly polarized light of intensity $I$ is incident on an analyser making an angle of $30^{\circ}$ with the axes of the polariser. The intensity of light emitted from the analyser will be:

Accepted Answer

1. **Concept (Malus' Law):** When a beam of completely plane-polarized light is incident on an analyser, the resultant intensity $I'$ transmitted from the analyser is given by the relation $I' = I \cos^2 	heta$, where $I$ is the intensity of incident polarized light and $	heta$ is the angle between the transmission axes of the polarizer and the analyser.
2. **Given Values:** 
   - Incident Intensity = $I$
   - Angle $	heta = 30^{\circ}$
3. **Calculation:**
   $$ I' = I \cos^2(30^{\circ}) $$
   $$ I' = I \left( \frac{\sqrt{3}}{2} ight)^2 $$
   $$ I' = I \left( \frac{3}{4} ight) = \frac{3I}{4} $$
4. **Conclusion:** The intensity of the light emitted is $3I/4$.

Step-by-Step Solution

Practice All PHYSICS Questions