An n-p-n transistor is connected in a common emitter configuration (see figure) in which collector voltage dro

Question

An n-p-n transistor is connected in a common emitter configuration (see figure) in which collector voltage drop across load resistance ($800\ \Omega$) connected to the collector circuit is $0.8	ext{ V}$. The collector current is:

Accepted Answer

The collector current ($I_C$) can be calculated using Ohm's law, given the voltage drop across the load resistance ($V_{R_L}$) and the load resistance ($R_L$).
Given:
Voltage drop across load resistance, $V_{R_L} = 0.8	ext{ V}$
Load resistance, $R_L = 800\ \Omega$
Collector current, $I_C = \frac{V_{R_L}}{R_L}$
$I_C = \frac{0.8}{800} = \frac{1}{1000}	ext{ A} = 10^{-3}	ext{ A} = 1	ext{ mA}$.

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