back to directory
NEET PHYSICSRAY OPTICS AND OPTICAL INSTRUMENTSMedium

Question

An observer is using an astronomical refracting telescope to observe planets in normal adjustment. The focal lengths of the objective and eyepiece used in the telescope construction are 20 m20 \text{ m} and 2 cm2 \text{ cm} respectively. Consider the following statements about the telescope: (A) The distance between the objective and the eyepiece is 20.02 m20.02 \text{ m}. (B) The magnification of the telescope is 1000-1000. (C) The image of the planet is erect and diminished. (D) The aperture of the eyepiece is smaller than that of the objective.

The correct statements are:

A

A, B, and C

B

B, C, and D

C

C, D, and A

D

A, B, and D

Step-by-Step Solution

  1. Analyze Given Data:
  • Focal length of objective (fof_o) = 20 m20 \text{ m}.
  • Focal length of eyepiece (fef_e) = 2 cm=0.02 m2 \text{ cm} = 0.02 \text{ m}.
  • Normal adjustment implies the final image is formed at infinity.
  1. Evaluate Statement A (Length):
  • In normal adjustment, the distance between the lenses (length of the telescope, LL) is the sum of their focal lengths.
  • L=fo+fe=20 m+0.02 m=20.02 mL = f_o + f_e = 20 \text{ m} + 0.02 \text{ m} = 20.02 \text{ m}.
  • Statement A is Correct.
  1. Evaluate Statement B (Magnification):
  • The magnifying power (mm) in normal adjustment is given by m=fo/fem = -f_o / f_e.
  • m=20/0.02=1000m = -20 / 0.02 = -1000.
  • The negative sign indicates the image is inverted.
  • Statement B is Correct.
  1. Evaluate Statement C (Image Nature):
  • An astronomical refracting telescope produces an inverted image. It is not erect.
  • Statement C is Incorrect.
  1. Evaluate Statement D (Aperture):
  • The objective lens must have a large aperture to gather sufficient light from distant objects and to provide high resolution (RPaRP \propto a). The eyepiece has a smaller aperture.
  • Statement D is Correct.
  1. Conclusion: Statements A, B, and D are correct.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from RAY OPTICS AND OPTICAL INSTRUMENTS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSRAY OPTICS AND OPTICAL INSTRUMENTSobserverastronomicalrefractingtelescopeobserve

More RAY OPTICS AND OPTICAL INSTRUMENTS Questions

View all

A horizontal ray of light is incident on a right-angled prism with a prism angle of $6^{\circ}$. If the refractive index of the material of the prism is 1.5, then the angle of emergence will be:

A.$9^{\circ}$
B.$10^{\circ}$
C.$4^{\circ}$
D.$6^{\circ}$
MediumSolve

A concave lens with a focal length of $-25 \text{ cm}$ is sandwiched between two convex lenses, each with a focal length of $40 \text{ cm}$. The power (in diopters) of the combined lens system would be:

A.5
B.9
C.1
D.0.01
MediumSolve

The refracting angle of a prism is $A$, and the refractive index of the material of the prism is $\cot(A/2)$. The angle of minimum deviation is:

A.$180^\circ - 3A$
B.$180^\circ - 2A$
C.$90^\circ - A$
D.$180^\circ + 2A$
MediumSolve

A small telescope has an objective of focal length $140\text{ cm}$ and an eyepiece of focal length $5.0\text{ cm}$. The magnifying power of the telescope for viewing a distant object is:

A.28
B.17
C.32
D.34
EasySolve

An astronomical telescope has an objective and eyepiece of focal lengths $40\text{ cm}$ and $4\text{ cm}$ respectively. To view an object $200\text{ cm}$ away from the objective, the lenses must be separated by a distance of:

A.46.0 cm
B.50.0 cm
C.54.0 cm
D.37.3 cm
MediumSolve

A plano-convex lens fits exactly into a plano-concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices $\mu_1$ and $\mu_2$ and $R$ is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is:

A.$\frac{R}{2(\mu_1+\mu_2)}$
B.$\frac{R}{2(\mu_1-\mu_2)}$
C.$\frac{R}{\mu_1-\mu_2}$
D.$\frac{2R}{\mu_2-\mu_1}$
MediumSolve

A double convex lens has a focal length of 25 cm. The radius of curvature of one of the surfaces is double of the other. What would be the radii if the refractive index of the material of the lens is 1.5?

A.100 cm, 50 cm
B.25 cm, 50 cm
C.18.75 cm, 37.5 cm
D.50 cm, 100 cm
MediumSolve

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. The refractive index of the material of the lens is:

A.4/3
B.9/8
C.5/3
D.3/2
MediumSolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →