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NEET PHYSICSLAWS OF MOTIONEasy

Question

Find the maximum velocity for skidding for a car moving on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2.

A

0.14 m/s

B

140 m/s

C

1.4 km/s

D

14 m/s

Step-by-Step Solution

  1. Identify the Principle: For a car moving on a level circular track, the necessary centripetal force is provided by the force of static friction between the tyres and the road [Source 69].
  2. Formula: The maximum safe speed (vmaxv_{max}) to avoid skidding is given by the condition where the maximum static friction equals the centripetal force: mvmax2R=μsmg\frac{mv_{max}^2}{R} = \mu_s mg vmax=μsRgv_{max} = \sqrt{\mu_s Rg} [Source 69, 70]
  3. Calculation:
  • Coefficient of friction (μs\mu_s) = 0.2
  • Radius (RR) = 100 m
  • Acceleration due to gravity (gg) 9.8 m/s2\approx 9.8 \text{ m/s}^2 Substitute the values: vmax=0.2×100×9.8v_{max} = \sqrt{0.2 \times 100 \times 9.8} vmax=196v_{max} = \sqrt{196} vmax=14 m/sv_{max} = 14 \text{ m/s}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from LAWS OF MOTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSLAWS OF MOTIONmaximumvelocityskiddingmovingcircular

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