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NEET PHYSICSSEMICONDUCTOR ELECTRONICSMedium

Question

In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table:

A

A B Y 0 0 0 0 1 1 1 0 1 1 1 1

B

A B Y 0 0 1 0 1 0 1 0 0 1 1 0

C

A B Y 0 0 0 0 1 0 1 0 0 1 1 1

D

A B Y 0 0 1 0 1 1 1 0 1 1 1 0

Step-by-Step Solution

Since the circuit diagram is missing from the question text, we refer to the standard AIPMT 2007 problem. The circuit typically consists of two diodes connected in parallel, which functions as an OR gate. When either input A or input B (or both) is at a high potential (logic 1), the respective diode is forward-biased and conducts, making the output Y high (logic 1). When both inputs A and B are at a low potential (logic 0), both diodes are reverse-biased and do not conduct, resulting in a low output Y (logic 0). This logic corresponds to the truth table of an OR gate.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from SEMICONDUCTOR ELECTRONICS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSSEMICONDUCTOR ELECTRONICSfollowingcircuitoutputpossibleinputs

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