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NEET PHYSICSNUCLEIEasy

Question

In the nuclear decay given below: ZAXZ+1AYZ1A4BZ1A4B_{Z}^{A}X \rightarrow _{Z+1}^{A}Y \rightarrow _{Z-1}^{A-4}B^* \rightarrow _{Z-1}^{A-4}B The particles emitted in the sequence are:

A

\beta , \alpha , \gamma

B

\gamma , \beta , \alpha

C

\beta , \gamma , \alpha

D

\alpha , \beta , \gamma

Step-by-Step Solution

  1. First Decay (XYX \rightarrow Y): The mass number (AA) remains the same, while the atomic number (ZZ) increases by 1 (ZZ+1Z \rightarrow Z+1). This indicates the conversion of a neutron into a proton with the emission of an electron (\beta particle). This is Beta (β\beta^-) decay.
  2. Second Decay (YBY \rightarrow B^*):The mass number decreases by 4 (AA4A \rightarrow A-4) and the atomic number decreases by 2 ((Z+1)2=Z1(Z+1) - 2 = Z-1). This corresponds to the emission of a helium nucleus (24He_{2}^{4}\text{He}). This isAlpha (α\alpha) decay. 3.Third Decay (BBB^* \rightarrow B):There is no change in either the mass number or the atomic number, but the nucleus transitions from an excited state (implied by the context of sequential decay ending in the same nucleus) to a lower energy state. This releases energy in the form of a high-energy photon. This isGamma (γ\gamma) decay. 4.Sequence: The order is β,α,γ\beta, \alpha, \gamma.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEInuclearrightarrowrightarrowrightarrowparticles

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