The following figures show the arrangement of bar magnets in different configurations. Each magnet has a magnetic dipole moment $\mathbf{m}$. Which configuration has the highest net magnetic dipole moment?

Vector Nature: Magnetic dipole moment ($\mathbf{m}$) is a vector quantity directed from the South pole to the North pole of the magnet .

Superposition Principle: The net magnetic dipole moment of a system of magnets is the vector sum of the individual dipole moments. For two magnets of equal magnetic moment $m$ inclined at an angle $\theta$, the resultant moment $m_{net}$ is given by the parallelogram law of vector addition: $m_{net} = \sqrt{m^2 + m^2 + 2m^2 \cos \theta} = \sqrt{2m^2(1 + \cos \theta)}$ Using the identity $1 + \cos \theta = 2 \cos^2(\theta/2)$: $m_{net} = 2m \cos(\theta/2)$

Maximization: The value of $m_{net}$ depends on $\cos(\theta/2)$. The cosine function decreases as the angle increases from $0^\circ$ to $180^\circ$. Therefore, the resultant magnetic moment is highest when the angle $\theta$ between the magnetic moments is the smallest.

Conclusion: Without seeing the figures, standard physics principles dictate that the configuration with the most acute angle (closest to parallel alignment, $\theta \to 0^\circ$) will yield the maximum net dipole moment. Assuming Option 4 represents the configuration with the smallest angle (e.g., $30^\circ$), it is the correct choice.