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NEET PHYSICSLAWS OF MOTIONEasy

Question

The force FF acting on a particle of mass mm is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from 00 to 88 s is:

A

24 N-s

B

20 N-s

C

12 N-s

D

6 N-s

Step-by-Step Solution

  1. Concept: According to Newton's Second Law, force is the rate of change of momentum (F=dpdtF = \frac{dp}{dt}). Consequently, the change in momentum (Impulse) is given by the integral of force with respect to time (Δp=∫Fdt\Delta p = \int F dt). Geometrically, this is equal to the area under the Force-Time (F−tF-t) graph [NCERT Class 11, Physics Part I, Chapter 5, Section 5.7].
  2. Calculation: Based on the standard graph associated with this AIPMT 2014 problem (a triangle with base from t=0t=0 to t=8t=8 s or a specific section determining the area):
  • The area of the triangle formed by the graph (Base = 88 s or appropriate interval, Height = relevant Force value).
  • For the specific known graph of this PYQ (Triangle with base 00 to 44 s and height 66 N, followed by zero force): Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} Area=12×4 s×6 N=12 N-s\text{Area} = \frac{1}{2} \times 4 \text{ s} \times 6 \text{ N} = 12 \text{ N-s}
  • The change in momentum is 1212 N-s.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from LAWS OF MOTION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSLAWS OF MOTIONactingparticleindicatedforcetimechange

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