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NEET PHYSICSGRAVITATIONEasy

Question

The radii of the circular orbits of two satellites A and B of the earth are 4R and R, respectively. If the speed of the satellite A is 3v, then the speed of the satellite B will be:

A

3v/4

B

6v

C

12v

D

3v/2

Step-by-Step Solution

The orbital speed (vov_o) of a satellite revolving in a circular orbit of radius rr around the Earth is given by vo=GMrv_o = \sqrt{\frac{GM}{r}}, where GG is the gravitational constant and MM is the mass of the Earth. From this relation, velocity is inversely proportional to the square root of the orbital radius: v1rv \propto \frac{1}{\sqrt{r}}. Therefore, the ratio of speeds is vBvA=rArB\frac{v_B}{v_A} = \sqrt{\frac{r_A}{r_B}}. Given: rA=4Rr_A = 4R, rB=Rr_B = R, and vA=3vv_A = 3v. Substituting these values: vB3v=4RR=4=2\frac{v_B}{3v} = \sqrt{\frac{4R}{R}} = \sqrt{4} = 2. vB=2×3v=6vv_B = 2 \times 3v = 6v.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from GRAVITATION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSGRAVITATIONcircularorbitssatellitesrespectivelysatellite

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