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NEET PHYSICSNUCLEIEasy

Question

The ratio of nuclear densities and nuclear volumes of 2656Fe{}_{26}^{56}\mathrm{Fe} and 24He{}_{2}^{4}\mathrm{He} are, respectively:

A

13:1 and 14:1

B

14:1 and 1:1

C

1:1 and 14:1

D

1:1 and 13:1

Step-by-Step Solution

  1. Nuclear Density: The nuclear radius RR is related to the mass number AA by R=R0A1/3R = R_0 A^{1/3} . The nuclear volume VV is 43πR3=43πR03A\frac{4}{3}\pi R^3 = \frac{4}{3}\pi R_0^3 A. Since the nuclear mass MM is proportional to AA (MmnAM \approx m_n A), the nuclear density ρ=MV\rho = \frac{M}{V} is independent of AA (constant for all nuclei). Therefore, the ratio of densities is 1:1.
  2. Nuclear Volume: As derived above, nuclear volume is directly proportional to the mass number (VAV \propto A).
  • For 2656Fe{}_{26}^{56}\mathrm{Fe}, A=56A = 56.
  • For 24He{}_{2}^{4}\mathrm{He}, A=4A = 4.
  • Ratio of volumes VFeVHe=564=141\frac{V_{\mathrm{Fe}}}{V_{\mathrm{He}}} = \frac{56}{4} = \frac{14}{1}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEInucleardensitiesnuclearvolumesmathrmfe

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