Back to Directory
NEET PHYSICSUNITS AND MEASUREMENTSMedium

Question

The velocity vv (in cm/sec\text{cm/sec}) of a particle is given in terms of time tt (in sec\text{sec}) by the relation v=at+bt+cv = at + \frac{b}{t+c}; the dimensions of aa, bb and cc are

A

a=L2,b=T,c=LT2a = L^2, b = T, c = L T^2

B

a=LT2,b=LT,c=La = L T^2, b = L T, c = L

C

a=LT2,b=L,c=Ta = L T^{-2}, b = L, c = T

D

a=L,b=LT,c=T2a = L, b = L T, c = T^2

Step-by-Step Solution

Explanation Unlocked on Signup

Join free — takes 30 seconds

Reveal Answer Free
Practice Mode Available

Practice All PHYSICS Questions

Analytics · Leaderboards · Full NEET Mock Tests · 15,000+ MCQs

Get Started Free

This NEET PHYSICS practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. Browse all NEET practice questions →

NEET PHYSICS: "The velocity $v$ (in $\text{cm/sec}$) of a particle is given in terms of time $t$ (in $\text{sec}$) by the relation $v =..." — Solved MCQ | TopperSquare