Question
Thermodynamic processes are indicated in the following diagram. Match the following:
Column-I (P) Process I (Q) Process II (R) Process III (S) Process IV
Column-II (a) Adiabatic (b) Isobaric (c) Isochoric (d) Isothermal
P → c, Q → a, R → d, S → b
P → c, Q → d, R → b, S → a
P → d, Q → b, R → b, S → c
P → a, Q → c, R → d, S → b
To match the processes with their corresponding P-V diagram curves, we apply the characteristics of thermodynamic processes for an ideal gas:
Isochoric Process (Constant Volume): The work done is zero, and the volume () remains constant while pressure () changes. On a P-V graph, this corresponds to a vertical line. Thus, Process I matches with (c) Isochoric.
Isobaric Process (Constant Pressure): The pressure () remains constant while volume changes. On a P-V graph, this corresponds to a horizontal line. Thus, Process IV matches with (b) Isobaric.
Isothermal vs. Adiabatic (Expansion): Both processes represent curves with negative slopes. However, the magnitude of the slope for an adiabatic process () is greater than that for an isothermal process () because the heat capacity ratio (gamma) is greater than 1. Therefore, the adiabatic curve is steeper (falls more rapidly) than the isothermal curve.
Matching: P (Process I) → c (Isochoric) Q (Process II) → a (Adiabatic) R (Process III) → d (Isothermal) S (Process IV) → b (Isobaric)
This sequence corresponds to Option 1 .
This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.
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