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NEET PHYSICSWORK, ENERGY AND POWEREasy

Question

Two bodies AA and BB of the same mass undergo completely inelastic one-dimensional collision. The body AA moves with velocity v1v_1 while the body BB is at rest before collision. The velocity of the system after collision is v2v_2. The ratio of v1:v2v_1 : v_2 is:

A

2:1

B

4:1

C

1:4

D

1:2

Step-by-Step Solution

  1. Identify the System: A completely inelastic collision occurs when two bodies stick together after impact and move with a common velocity. Momentum is conserved, but kinetic energy is not.
  2. Apply Conservation of Linear Momentum: mAv1i+mBv2i=(mA+mB)vfm_A v_{1i} + m_B v_{2i} = (m_A + m_B)v_f Given: mA=mB=mm_A = m_B = m, initial velocity of A is v1v_1, initial velocity of B is 00, and final common velocity is v2v_2. m(v1)+m(0)=(m+m)v2m(v_1) + m(0) = (m + m)v_2 mv1=2mv2mv_1 = 2mv_2
  3. Calculate Ratio: v1=2v2v_1 = 2v_2 v1v2=21\frac{v_1}{v_2} = \frac{2}{1} [Class 11 Physics, Ch 6, Sec 5.11]

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from WORK, ENERGY AND POWER. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSWORK, ENERGY AND POWERbodiesundergocompletelyinelasticonedimensional

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