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NEET PHYSICSMOTION IN A PLANEEasy

Question

Two bodies are projected with the same velocity. If one is projected at an angle of 3030^{\circ} and the other at an angle of 6060^{\circ} to the horizontal, the ratio of the maximum heights reached is:

A

3 : 1

B

1 : 3

C

1 : 2

D

2 : 1

Step-by-Step Solution

  1. Formula for Maximum Height: The maximum height HH reached by a projectile is given by the equation: H=v02sin2θ2gH = \frac{v_0^2 \sin^2 \theta}{2g} .
  2. Comparison: Since the initial velocity v0v_0 and acceleration due to gravity gg are the same for both bodies, the height is directly proportional to sin2θ\sin^2 \theta. Hsin2θH \propto \sin^2 \theta
  3. Calculation: For the first body (θ1=30\theta _1 = 30^{\circ}): H1sin230=(1/2)2=1/4H_1 \propto \sin^2 30^{\circ} = (1/2)^2 = 1/4. For the second body (θ2=60\theta _2 = 60^{\circ}): H2sin260=(3/2)2=3/4H_2 \propto \sin^2 60^{\circ} = (\sqrt{3}/2)^2 = 3/4.
  4. Ratio: H1H2=1/43/4=13\frac{H_1}{H_2} = \frac{1/4}{3/4} = \frac{1}{3}. The ratio is 1 : 3.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A PLANE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A PLANEbodiesprojectedvelocityprojectedhorizontal

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