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NEET PHYSICSNUCLEIEasy

Question

Two nuclei have their mass numbers in the ratio of 1:3. The ratio of their nuclear densities would be:

A

1:3

B

3:1

C

(3)^{1/3} : 1

D

1:1

Step-by-Step Solution

  1. Formula for Nuclear Density: Nuclear density (ρ\rho) is defined as the mass of the nucleus divided by its volume.
  2. Mass and Volume Relations: Mass (MM) is proportional to the mass number (AA): MA×mnM \approx A \times m_n (where mnm_n is the mass of a nucleon). Radius (RR) is proportional to the cube root of the mass number: R=R0A1/3R = R_0 A^{1/3}.
  • Volume (VV) is proportional to the cube of the radius: V=43πR3=43πR03AV = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi R_0^3 A.
  1. Density Calculation: ρ=MV=Amn43πR03A=3mn4πR03\rho = \frac{M}{V} = \frac{A \cdot m_n}{\frac{4}{3}\pi R_0^3 A} = \frac{3 m_n}{4\pi R_0^3}
  2. Conclusion: The mass number (AA) cancels out, meaning nuclear density is independent of the mass number. It is approximately constant for all nuclei. Therefore, the ratio of nuclear densities for any two nuclei is always 1:1.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEInucleinumbersnucleardensities

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