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NEET PHYSICSWave OpticsMedium

Question

Unpolarised light is incident from the air on a plane surface of a material of refractive index μ\mu. At a particular angle of incidence ii, it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation?

A

the reflected light is polarised with its electric vector parallel to the plane of incidence.

B

the reflected light is polarised with its electric vector perpendicular to the plane of incidence.

C

i=sin1(1μ)i = \sin^{-1}\left(\frac{1}{\mu}\right)

D

i=tan1(1μ)i = \tan^{-1}\left(\frac{1}{\mu}\right)

Step-by-Step Solution

When unpolarised light is incident at a particular angle such that the reflected and refracted rays are perpendicular to each other, this angle of incidence is called Brewster's angle (iBi_B). According to Brewster's law, μ=taniB    i=tan1(μ)\mu = \tan i_B \implies i = \tan^{-1}(\mu). At this angle, the reflected light is completely plane-polarised, and its electric field vector is perpendicular to the plane of incidence.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Wave Optics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSWave Opticsunpolarisedincidentsurfacematerialrefractive

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