Torque is defined as the cross product of the position vector and the force vector: $\vec{\tau} = \vec{r} \times \vec{F}$. Given: Position vector, $\vec{r} = 2\hat{k} \text{ m}$ Force vector, $\vec{F} = 3\hat{j} \text{ N}$ $\vec{\tau} = (2\hat{k}) \times (3\hat{j})$ $\vec{\tau} = 6(\hat{k} \times \hat{j})$ Since $\hat{k} \times \hat{j} = -\hat{i}$, we get: $\vec{\tau} = -6\hat{i} \text{ N-m}$