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NEET CHEMISTRYSome Basic Concepts of ChemistryEasy

Question

A mixture of gases contains H2\text{H}_2 and O2\text{O}_2 gases in the ratio of 1:41:4 (w/w). What is the molar ratio of the two gases in the mixture?

A

1:41:4

B

4:14:1

C

16:116:1

D

2:12:1

Step-by-Step Solution

Let the mass of H2\text{H}_2 in the mixture be w gw \text{ g}. Then, the mass of O2\text{O}_2 will be 4w g4w \text{ g}. The molar mass of H2\text{H}_2 is 2 g mol12 \text{ g mol}^{-1} and the molar mass of O2\text{O}_2 is 32 g mol132 \text{ g mol}^{-1} . Number of moles is calculated as the ratio of given mass to the molar mass . Number of moles of H2=Mass of H2Molar mass of H2=w2\text{H}_2 = \frac{\text{Mass of H}_2}{\text{Molar mass of H}_2} = \frac{w}{2} Number of moles of O2=Mass of O2Molar mass of O2=4w32=w8\text{O}_2 = \frac{\text{Mass of O}_2}{\text{Molar mass of O}_2} = \frac{4w}{32} = \frac{w}{8} The molar ratio of H2\text{H}_2 to O2=w2w8=82=41=4:1\text{O}_2 = \frac{\frac{w}{2}}{\frac{w}{8}} = \frac{8}{2} = \frac{4}{1} = 4:1.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Some Basic Concepts of Chemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYSome Basic Concepts of Chemistrymixturecontainsmixture

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