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NEET CHEMISTRYChemical Bonding and Molecular StructureEasy

Question

Among the options given below, identify the isoelectronic species:

A

CO,CN,NO+,C22CO, CN^{-}, NO^{+}, C_{2}^{2-}

B

CO,CN,NO,C2CO^{-}, CN, NO, C_{2}^{-}

C

CO+,CN+,NO,C2CO^{+}, CN^{+}, NO^{-}, C_{2}

D

CO,CN,NO,C2CO, CN, NO, C_{2}

Step-by-Step Solution

Isoelectronic species are defined as atoms, ions, or molecules that possess the same total number of electrons . To identify the correct set, the total electron count for each species in Option A is calculated using their atomic numbers (ZZ) and ionic charges :

  1. COCO: Carbon (Z=6Z=6) + Oxygen (Z=8Z=8) = 1414 electrons .
  2. CNCN^{-}: Carbon (66) + Nitrogen (77) + 11 (for the negative charge) = 1414 electrons .
  3. NO+NO^{+}: Nitrogen (77) + Oxygen (88) - 11 (for the positive charge) = 1414 electrons .
  4. C22C_{2}^{2-}: Two Carbon atoms (2×62 \times 6) + 22 (for the 22- charge) = 1414 electrons.

Since every species in this group has exactly 1414 electrons, they are isoelectronic . Other options are incorrect because they include species with different electron counts, such as NONO (15 electrons) or CNCN (13 electrons) .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structureoptionsidentifyisoelectronicspecies

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