An alkene "A" on reaction with $O_3$ and $Zn-H_2O$ gives propanone and ethanal in equimolar ratio. Addition of

Question

An alkene "A" on reaction with $O_3$ and $Zn-H_2O$ gives propanone and ethanal in equimolar ratio. Addition of $HCl$ to alkene "A" gives "B" as the major product. The structure of product "B" is:

Accepted Answer

Ozonolysis of alkene A gives propanone ($CH_3COCH_3$) and ethanal ($CH_3CHO$). The alkene is 2-methylpent-2-ene. Addition of $HCl$ follows Markovnikov's rule to give 2-chloro-2-methylpentane.

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