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Consider the following reaction : C6H5CH2OC6H5HI,ΔA+B\text{C}_6\text{H}_5-\text{CH}_2-\text{O}-\text{C}_6\text{H}_5 \xrightarrow{\text{HI}, \Delta} \text{A} + \text{B}. Identify products A and B.

A
B
C
D

Step-by-Step Solution

The reaction of an alkyl aryl ether with HI involves the cleavage of the C-O bond. The bond between the oxygen and the alkyl group (benzyl) is cleaved because the benzyl carbocation is stabilized by resonance. Thus, the products are benzyl iodide (C6H5CH2I\text{C}_6\text{H}_5\text{CH}_2\text{I}) and phenol (C6H5OH\text{C}_6\text{H}_5\text{OH}).

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