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Identify the product in the following reaction:

C6H5N2Cl(ii)Mg/dryether(i)Cu2Br2/HBr(iii)H2OProductC_6H_5N_2Cl \xrightarrow[(ii) Mg/dry ether]{(i) Cu_2Br_2/HBr} \xrightarrow[(iii) H_2O]{} Product

A

Bromobenzene

B

Benzene

C

Phenol

D

Phenylmagnesium bromide

Step-by-Step Solution

The reaction sequence is: 1. Sandmeyer reaction of benzenediazonium chloride (C6H5N2ClC_6H_5N_2Cl) with Cu2Br2/HBrCu_2Br_2/HBr gives bromobenzene (C6H5BrC_6H_5Br). 2. Reaction of bromobenzene with Mg in dry ether forms the Grignard reagent, phenylmagnesium bromide (C6H5MgBrC_6H_5MgBr). 3. Hydrolysis of the Grignard reagent with H2OH_2O yields benzene (C6H6C_6H_6).

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