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NEET CHEMISTRYClassification of Elements and Periodicity in PropertiesEasy

Question

If an atom has electronic configuration 1s22s22p63s23p63d34s21s^2 2s^2 2p^6 3s^2 3p^6 3d^3 4s^2, we will place it in group number:

A

Fifth

B

Fifteenth

C

Second

D

Third

Step-by-Step Solution

  1. Identify the Block: The electronic configuration ends with electrons filling the 3d3d orbital (3d33d^3) after the 4s4s orbital (4s24s^2). This indicates the element belongs to the d-block (Transition Elements).
  2. Determine the Group Number: For d-block elements, the group number is calculated as the sum of electrons in the (n1)d(n-1)d subshell and the nsns subshell. Group Number = (Number of electrons in 3d3d) + (Number of electrons in 4s4s) Group Number = 3+2=53 + 2 = 5
  3. Identify the Element (Optional): The total number of electrons is 2+2+6+2+6+3+2=232+2+6+2+6+3+2 = 23. The element with atomic number 23 is Vanadium (V), which lies in Group 5.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Classification of Elements and Periodicity in Properties. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYClassification of Elements and Periodicity in Propertieselectronicconfigurationnumber

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A.Ar < K⁺ < Ca²⁺
B.Ca²⁺ < Ar < K⁺
C.Ca²⁺ < K⁺ < Ar
D.K⁺ < Ar < Ca²⁺
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Which one of the following represents all isoelectronic species?

A.Na⁺, Cl⁻, O⁻, NO⁺
B.N₂O, N₂O₄, NO⁺, NO
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D.Ca²⁺, Ar, K⁺, Cl⁻
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The value of electron gain enthalpy of $Na^+$, if $IE_1$ of Na = 5.1 eV, is:

A.+10.2 eV
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C.–10.2 eV
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A.H⁺
B.Li⁺
C.Na⁺
D.Mg²⁺
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Identify the correct order of the size of the following species: $Ca^{2+}, K^+, Ar, S^{2-}, Cl^-$

A.$Ca^{2+} < K^+ < Ar < S^{2-} < Cl^-$
B.$Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}$
C.$Ar < Ca^{2+} < K^+ < Cl^- < S^{2-}$
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A.Si < C < O < N < F
B.O < F < N < C < Si
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A.Cr > Mn > V > Ti
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