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NEET CHEMISTRYClassification of Elements and Periodicity in PropertiesEasy

Question

Which of the following arrangements is correct for increasing order of electronegativity?

A

Si < C < O < N < F

B

O < F < N < C < Si

C

F < O < N < C < Si

D

Si < C < N < O < F

Step-by-Step Solution

Electronegativity generally increases across a period from left to right and decreases down a group.

  1. Period 2 Elements: Carbon (C), Nitrogen (N), Oxygen (O), and Fluorine (F) are in the same period. The order of electronegativity increases as C<N<O<FC < N < O < F (Values: C=2.5, N=3.0, O=3.5, F=4.0).
  2. Comparison with Silicon (Si): Silicon is in Group 14, below Carbon. Electronegativity decreases down a group, so Si<CSi < C (Value for Si=1.8).

Combining these trends, the correct increasing order is Si<C<N<O<FSi < C < N < O < F.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Classification of Elements and Periodicity in Properties. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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