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NEET CHEMISTRYClassification of Elements and Periodicity in PropertiesMedium

Question

Which of the following pair is correctly matched?

A

Basic oxides - In₂O₃, K₂O, SnO₂

B

Neutral oxides - CO, NO₂, N₂O

C

Acidic oxides - Mn₂O₇, SO₂, TeO₃

D

Amphoteric oxides - BeO, Ga₂O₃, GeO

Step-by-Step Solution

  1. Acidic Oxides: According to NCERT , as the oxidation number of a metal increases, ionic character decreases and acidic character increases. Mn2O7Mn_2O_7 is explicitly cited as an acidic oxide that gives HMnO4HMnO_4 with water. SO2SO_2 is a non-metal oxide located on the right side of the periodic table, which are acidic . TeO3TeO_3 (Group 16) is also an acidic oxide.
  2. Neutral Oxides: NCERT lists CO, NO, and N2ON_2O as neutral oxides. However, NO2NO_2 is an acidic oxide (mixed anhydride of nitric and nitrous acid), making this option incorrect.
  3. Basic Oxides: K2OK_2O is a strongly basic oxide. However, SnO2SnO_2 is well-known as an amphoteric oxide, not a basic one.
  4. Amphoteric Oxides: BeOBeO and Ga2O3Ga_2O_3 are amphoteric. GeOGeO is distinct from the group; oxides of Group 14 elements in lower oxidation states (like CO) are often neutral or weakly acidic/amphoteric, but the grouping in Option 3 is the most definitively correct set according to periodic trends described in the texts.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Classification of Elements and Periodicity in Properties. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYClassification of Elements and Periodicity in Propertiesfollowingcorrectlymatched

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The correct sequence of increasing radii is:

A.Ar < K⁺ < Ca²⁺
B.Ca²⁺ < Ar < K⁺
C.Ca²⁺ < K⁺ < Ar
D.K⁺ < Ar < Ca²⁺
EasySolve

Which one of the following represents all isoelectronic species?

A.Na⁺, Cl⁻, O⁻, NO⁺
B.N₂O, N₂O₄, NO⁺, NO
C.Na⁺, Mg²⁺, O⁻, F⁻
D.Ca²⁺, Ar, K⁺, Cl⁻
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The value of electron gain enthalpy of $Na^+$, if $IE_1$ of Na = 5.1 eV, is:

A.+10.2 eV
B.–5.1 eV
C.–10.2 eV
D.+2.55 eV
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Be²⁺ is isoelectronic with which of the following ions?

A.H⁺
B.Li⁺
C.Na⁺
D.Mg²⁺
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Identify the correct order of the size of the following species: $Ca^{2+}, K^+, Ar, S^{2-}, Cl^-$

A.$Ca^{2+} < K^+ < Ar < S^{2-} < Cl^-$
B.$Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}$
C.$Ar < Ca^{2+} < K^+ < Cl^- < S^{2-}$
D.$Ca^{2+} < Ar < K^+ < Cl^- < S^{2-}$
MediumSolve

The formation of the oxide ion O²⁻(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g) + e⁻ → O⁻(g); ΔH° = -141 kJ mol⁻¹ O⁻(g) + e⁻ → O²⁻(g); ΔH° = +780 kJ mol⁻¹ Thus, the process of formation of O²⁻ in gas phase is unfavourable even though O²⁻ is isoelectronic with neon. It is due to the fact that:

A.Electron repulsion outweighs the stability gained by achieving noble gas configuration
B.O⁻ ion has comparatively smaller size than oxygen atom
C.Oxygen is more electronegative
D.Addition of electron in oxygen result in large size of the ion
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Which of the following arrangements is correct for increasing order of electronegativity?

A.Si < C < O < N < F
B.O < F < N < C < Si
C.F < O < N < C < Si
D.Si < C < N < O < F
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The correct order of decreasing second ionization enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is:

A.Cr > Mn > V > Ti
B.V > Mn > Cr > Ti
C.Mn > Cr > Ti > V
D.Ti > V > Cr > Mn
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