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NEET CHEMISTRYP Block ElementsMedium

Question

Match List-I with List-II: List-I (Compounds) (a) Borax (b) Kernite (c) Orthoboric acid (d) Borax bead List-II (Molecular formula) (i) NaBO2+B2O3NaBO_2 + B_2O_3 (ii) Na2B4O7⋅4H2ONa_2B_4O_7 \cdot 4H_2O (iii) H3BO3H_3BO_3 (iv) Na2B4O7⋅10H2ONa_2B_4O_7 \cdot 10H_2O Choose the correct answer from the options given below:

A

(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)

B

(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

C

(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)

D

(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

Step-by-Step Solution

Let us match the compounds with their molecular formulas: (a) Borax: It is sodium tetraborate decahydrate, Na2B4O7⋅10H2ONa_2B_4O_7 \cdot 10H_2O. (b) Kernite: It is sodium tetraborate tetrahydrate, Na2B4O7⋅4H2ONa_2B_4O_7 \cdot 4H_2O. (c) Orthoboric acid: It is a weak monobasic Lewis acid with the formula H3BO3H_3BO_3. (d) Borax bead: On strong heating, borax loses its water of crystallization and forms a transparent glassy bead consisting of sodium metaborate (NaBO2NaBO_2) and boric anhydride/oxide (B2O3B_2O_3). Therefore, the correct matching is (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementslistiicompoundskerniteorthoboriclistii

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