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NEET CHEMISTRYP Block ElementsEasy

Question

Match the allotropes of carbon given in List I with the respective characteristics given in List II.

List-I (A) Coke (B) Diamond (C) Fullerene (D) Graphite

List-II I. Carbon atoms are sp3sp^3 hybridised. II. Used as a dry lubricant III. Used as a reducing agent IV. Cage like molecules

Choose the correct answer from the options given below:

A

(A)-III, (B)-IV, (C)-I, (D)-II

B

(A)-II, (B)-IV, (C)-I, (D)-III

C

(A)-IV, (B)-I, (C)-II, (D)-III

D

(A)-III, (B)-I, (C)-IV, (D)-II

Step-by-Step Solution

Let us match each allotrope of carbon with its characteristic property:

  1. Coke: It is a carbonaceous solid used extensively as a reducing agent in various metallurgical processes.
  2. Diamond: Each carbon atom undergoes sp3sp^3 hybridisation and is tetrahedrally bonded to four other carbon atoms, forming a rigid 3D network.
  3. Fullerene: They are discrete, hollow, cage-like carbon molecules (e.g., C60C_{60}, Buckminsterfullerene).
  4. Graphite: It consists of planar layers of sp2sp^2 hybridised carbon atoms. The weak van der Waals forces between these layers allow them to slip over one another, making graphite soft, slippery, and an excellent dry lubricant. Therefore, the correct matching is (A)-III, (B)-I, (C)-IV, (D)-II.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from P Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYP Block Elementsallotropescarbonrespectivecharacteristicsdiamond

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