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NEET CHEMISTRYChemical Bonding and Molecular StructureMedium

Question

Match the compounds given in Column I with the hybridization and shape given in Column II and mark the correct option.

Column I (A) XeF₆ (B) XeO₃ (C) XeOF₄ (D) XeF₄

Column II (1) Distorted octahedral (2) Square planar (3) Pyramidal (4) Square pyramidal

A

A-1, B-2, C-4, D-3

B

A-4, B-3, C-1, D-2

C

A-4, B-1, C-2, D-3

D

A-1, B-3, C-4, D-2

Step-by-Step Solution

  1. Analyze XeF₆ (A): Xenon (8 valence e−e^-) forms 6 bonds with Fluorine. Remaining electrons: 8−6=28-6=2 (1 Lone Pair). Steric number = 7 (sp3d3sp^3d^3). Structure: Distorted octahedral. Matches (1).
  2. Analyze XeO₃ (B): Xenon forms 3 double bonds with Oxygen (uses 6 e−e^-). Remaining: 8−6=28-6=2 (1 Lone Pair). Steric number = 4 (sp3sp^3). Structure: Pyramidal. Matches (3).
  3. Analyze XeOF₄ (C): Xenon forms 1 double bond with Oxygen and 4 single bonds with Fluorine. Total valence e−e^- used: 2(O)+4(F)=62(O) + 4(F) = 6. Remaining: 8−6=28-6=2 (1 Lone Pair). Steric number = 6 (sp3d2sp^3d^2). Structure: Square pyramidal. Matches (4).
  4. Analyze XeF₄ (D): Xenon forms 4 bonds with Fluorine. Remaining: 8−4=48-4=4 (2 Lone Pairs). Steric number = 6 (sp3d2sp^3d^2). Structure: Square planar. Matches (2).
  5. Conclusion: The correct sequence is A-1, B-3, C-4, D-2.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structurecompoundscolumnhybridizationcolumncorrect

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