Match the molecules in List-I with the corresponding shape in List-II:

List-I (Molecules):
(a) $NH_3$
(b) $Cl

Question

Match the molecules in List-I with the corresponding shape in List-II:

List-I (Molecules):
(a) $NH_3$
(b) $ClF_3$
(c) $PCl_5$
(d) $BrF_5$

List-II (Shape):
(i) Square pyramidal
(ii) Trigonal bipyramidal
(iii) Trigonal pyramidal
(iv) T-shape

Choose the correct answer from the options given below:

Accepted Answer

According to the VSEPR theory and hybridisation principles detailed in the sources:

1.  **$NH_3$ (a)**: The central nitrogen atom is $sp^3$ hybridised and has three bond pairs and one lone pair. The repulsion between the lone pair and bond pairs reduces the bond angle and results in a **trigonal pyramidal** shape .
2.  **$ClF_3$ (b)**: The chlorine atom undergoes $sp^3d$ hybridisation. It has three bond pairs and two lone pairs. To minimise repulsions, the lone pairs occupy equatorial positions, resulting in a **T-shape** .
3.  **$PCl_5$ (c)**: The phosphorus atom is $sp^3d$ hybridised and forms five bond pairs with no lone pairs. This results in a regular **trigonal bipyramidal** geometry .
4.  **$BrF_5$ (d)**: Bromine is $sp^3d^2$ hybridised with five bond pairs and one lone pair, which gives the molecule a **square pyramidal** shape .

Matching these correctly gives: (a)-(iii), (b)-(iv), (c)-(ii), and (d)-(i).

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