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NEET CHEMISTRYChemical Bonding and Molecular StructureMedium

Question

Paramagnetic species among the following is:

A

CO\text{CO}

B

O2\text{O}_2^-

C

CN\text{CN}^-

D

NO+\text{NO}^+

Step-by-Step Solution

According to Molecular Orbital Theory, species with unpaired electrons are paramagnetic. Let us calculate the total number of electrons for each species:

  • CO\text{CO}: 6 (C)+8 (O)=146 \text{ (C)} + 8 \text{ (O)} = 14 electrons. It has no unpaired electrons and is diamagnetic.
  • O2\text{O}_2^-: 16 (O2)+1=1716 \text{ (O}_2\text{)} + 1 = 17 electrons. Its electronic configuration is σ1s2σ1s2σ2s2σ2s2σ2pz2(π2px2=π2py2)(π2px2=π2py1)\sigma 1s^2 \sigma^* 1s^2 \sigma 2s^2 \sigma^* 2s^2 \sigma 2p_z^2 (\pi 2p_x^2 = \pi 2p_y^2) (\pi^* 2p_x^2 = \pi^* 2p_y^1). It has 1 unpaired electron in the antibonding π\pi^* orbital, making it paramagnetic.
  • CN\text{CN}^-: 6 (C)+7 (N)+1=146 \text{ (C)} + 7 \text{ (N)} + 1 = 14 electrons. It has no unpaired electrons and is diamagnetic.
  • NO+\text{NO}^+: 7 (N)+8 (O)1=147 \text{ (N)} + 8 \text{ (O)} - 1 = 14 electrons. It has no unpaired electrons and is diamagnetic. Therefore, O2\text{O}_2^- is the only paramagnetic species among the given options.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structureparamagneticspeciesfollowing

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