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NEET CHEMISTRYHaloalkanes and HaloarenesMedium

Question

The compound that will react most readily with gaseous bromine has the formula:

A

C3H6\text{C}_3\text{H}_6

B

C2H2\text{C}_2\text{H}_2

C

C4H10\text{C}_4\text{H}_{10}

D

C2H4\text{C}_2\text{H}_4

Step-by-Step Solution

Reaction with gaseous bromine is an electrophilic addition reaction. Alkenes (like C3H6\text{C}_3\text{H}_6 and C2H4\text{C}_2\text{H}_4) are generally more reactive than alkynes (C2H2\text{C}_2\text{H}_2) towards electrophilic addition because the π\pi-electrons in alkynes are more tightly held by the more electronegative sp-hybridised carbon atoms. Alkanes (C4H10\text{C}_4\text{H}_{10}) do not undergo addition reactions and only react via free-radical substitution under drastic conditions (e.g., UV light or heat). Between the two alkenes, propene (C3H6\text{C}_3\text{H}_6) is more reactive than ethene (C2H4\text{C}_2\text{H}_4). This is because the electron-donating methyl group in propene exerts a +I+I (inductive) effect and hyperconjugation, which increases the electron density on the carbon-carbon double bond, making it more susceptible to electrophilic attack by Br2\text{Br}_2.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Haloalkanes and Haloarenes. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYHaloalkanes and Haloarenescompoundreadilygaseousbromineformula

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