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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

The correct order of electronegativity of hybrid orbitals of carbon is:

A

sp>sp2>sp3sp > sp^2 > sp^3

B

sp<sp2<sp3sp < sp^2 < sp^3

C

sp≈sp2≈sp3sp \approx sp^2 \approx sp^3

D

sp>sp3>sp2sp > sp^3 > sp^2

Step-by-Step Solution

The change in hybridisation affects the electronegativity of carbon. The greater the s-character of the hybrid orbitals, the closer its electrons are to the nucleus, and thus, the greater is its electronegativity. The s-character in spsp, sp2sp^2, and sp3sp^3 hybrid orbitals is 50%, 33.33%, and 25%, respectively. Therefore, a carbon atom having an spsp hybrid orbital is more electronegative than that possessing sp2sp^2 or sp3sp^3 hybridised orbitals. The correct decreasing order of electronegativity is sp>sp2>sp3sp > sp^2 > sp^3.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques correctelectronegativityhybridorbitalscarbon

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