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NEET CHEMISTRYChemical Bonding and Molecular StructureMedium

Question

The correct order of increasing bond length of C-H\text{C-H}, C-O\text{C-O}, C-C\text{C-C} and C=C\text{C=C} is:

A

C-C<C=C<C-O<C-H\text{C-C} < \text{C=C} < \text{C-O} < \text{C-H}

B

C-O<C-H<C-C<C=C\text{C-O} < \text{C-H} < \text{C-C} < \text{C=C}

C

C-H<C-O<C-C<C=C\text{C-H} < \text{C-O} < \text{C-C} < \text{C=C}

D

C-H<C=C<C-O<C-C\text{C-H} < \text{C=C} < \text{C-O} < \text{C-C}

Step-by-Step Solution

Bond length is determined by the size of the bonded atoms and the multiplicity of the bond.

  1. C-H\text{C-H}: Hydrogen is the smallest atom, resulting in the shortest bond length (107 pm107\text{ pm}).
  2. C=C\text{C=C}: A double bond is shorter than a single bond due to greater orbital overlap and stronger attraction pulling the nuclei closer together (133 pm133\text{ pm}).
  3. C-O\text{C-O}: Oxygen has a smaller atomic radius than carbon, making the C-O\text{C-O} single bond (143 pm143\text{ pm}) shorter than a C-C\text{C-C} single bond.
  4. C-C\text{C-C}: A single bond between two carbon atoms has the longest bond length among these choices (154 pm154\text{ pm}). Therefore, the correct increasing order of bond lengths is C-H<C=C<C-O<C-C\text{C-H} < \text{C=C} < \text{C-O} < \text{C-C}.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Bonding and Molecular Structure. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Bonding and Molecular Structurecorrectincreasinglengthtextchtextco

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