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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Medium

Question

The correct shape and hybridisation of BrF5_5 is:

A

Square pyramidal and sp3^3d2^2

B

Square pyramidal and d2^2sp3^3

C

Trigonal bipyramidal and sp3^3d2^2

D

Trigonal bipyramidal and d2^2sp3^3

Step-by-Step Solution

  1. Determine Hybridisation: The central atom is Bromine (Br), which has 7 valence electrons. It forms single bonds with 5 Fluorine (F) atoms. Using the formula H=12(V+M−C+A)H = \frac{1}{2}(V + M - C + A), where V=7V=7 and M=5M=5: H=12(7+5)=6H = \frac{1}{2}(7 + 5) = 6. A steric number of 6 corresponds to sp3^3d2^2 hybridisation .
  2. Determine Bond Pairs and Lone Pairs: There are 5 bonding pairs (Br-F). The number of lone pairs is H−Bond Pairs=6−5=1H - \text{Bond Pairs} = 6 - 5 = 1.
  3. Determine Shape: The electron geometry for sp3^3d2^2 is octahedral. However, with 5 bond pairs and 1 lone pair (AB5_5E type), the molecular shape becomes Square Pyramidal .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques correcthybridisation

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